Consider two potassium salts S1 and S2 with the following observations: S1 + dil. HCl (ice-cold) - Product P1 (diazonium salt) - mild acidic conditions - Azo dye CuSO4(aq) + S2 - Product P2 (precipitate) + K2SO4 + poisonous gas G P1 + P2 undergo Sandmeyer's reaction Identify Salt S2.

Question

Consider two potassium salts S1 and S2 with the following observations: S1 + dil. HCl (ice-cold) -> Product P1 (diazonium salt) -> mild acidic conditions -> Azo dye CuSO4(aq) + S2 -> Product P2 (precipitate) + K2SO4 + poisonous gas G P1 + P2 undergo Sandmeyer's reaction Identify Salt S2.

Accepted Answer

KCN. S2 is KCN because it reacts with CuSO4 to give CuCN precipitate (P2) and HCN (poisonous gas G). CuCN participates in Sandmeyer's reaction with the diazonium salt P1 to give aryl nitrile.

Consider two potassium salts S1 and S2 with the following observations: S1 + dil. HCl (ice-cold) -> Product P1 (diazonium salt) -> mild acidic conditions -> Azo dye CuSO4(aq) + S2 -> Product P2 (precipitate) + K2SO4 + poisonous gas G P1 + P2 undergo Sandmeyer's reaction Identify Salt S2.

Solution

Related JEE Advanced Chemistry questions