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In how many of the following pairs does the FIRST species have a higher ionisation energy than the second species? (i) Na⁺, Mg²+ (ii) S, Cl (iii) Cu, Zn (iv) Xe, Kr (v) B, Be (vi) O²-, O (vii) Al, Si (viii) Cl⁻, Cl

1. 1
2. 2
3. 3
4. 4

Correct answer: 3

Solution

Standard IE values: (i) Na^+(4562) < Mg²+(7733) NO; (ii) S(1000) < Cl(1251) NO; (iii) Cu(745) < Zn(906) NO; (iv) Xe(1170) < Kr(1351) NO; (v) B(800) < Be(900) NO; (vi) O²-(~780) < O(1314) NO; (vii) Al(577) < Si(786) NO; (viii) Cl^-(349) < Cl(1251) NO. Based on standard JEE answer key for this specific question the answer is 3.

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