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A radioactive isotope undergoes decay by emitting 7 alpha particles and 6 beta particles to eventually form a stable product. What is the difference between the atomic number of the original radioactive isotope and that of the stable product?

1. 4
2. 6
3. 8
4. 10

Correct answer: 8

Solution

Seven alpha emissions reduce the atomic number by 14, while six beta emissions increase it by 6, giving a net decrease of 8. The difference in atomic number between parent and daughter is 8.

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