Exams › JEE Advanced › Chemistry
Match each product in List-I with the reaction from List-II that produces it: List-I: (P) H2O2 (Q) H2O2 + O2 (R) H2 (S) H2O List-II: (1) KO2 + H2O -> (2) Na2O2 + H2O -> (3) NaCl(aq) Electrolysis -> (4) NaCl + H2SO4 -> (5) NaHCO3 heated ->
- P -> 1; Q -> 2; R -> 3; S -> 4
- P -> 2; Q -> 1; R -> 3; S -> 5
- P -> 2; Q -> 1; R -> 3; S -> 4
- P -> 1; Q -> 2; R -> 4; S -> 5
Correct answer: P -> 2; Q -> 1; R -> 3; S -> 5
Solution
Na2O2 + 2H2O -> 2NaOH + H2O2 (P -> 2). 4KO2 + 2H2O -> 4KOH + 3O2 +... actually 2KO2 + 2H2O -> 2KOH + H2O2 + O2 (Q -> 1). Electrolysis of NaCl(aq): cathode: 2H2O + 2e⁻ -> H2 + 2OH⁻ (R -> 3). 2NaHCO3 -> Na2CO3 + H2O + CO2 (S -> 5). NaCl + H2SO4 -> NaHSO4 + HCl, not H2 (so option 4 is not in our matching).
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