Exams › JEE Advanced › Chemistry
Correct answer: (D) Ph-NH2
Hofmann bromamide reaction works for both aliphatic and aromatic amides, giving primary amines (RNH2 from RCONH2). Gabriel phthalimide synthesis requires an alkyl halide (SN2 on N of phthalimide); aryl halides (PhBr) are unreactive under these conditions, so aniline (Ph-NH2) cannot be made by Gabriel. CH3NH2 can be made by both Gabriel and Hofmann. Secondary and tertiary amines (Me2NH, Me3N) do not give a positive isocyanide test. Aniline (Ph-NH2) is a primary amine, gives positive isocyanide test, can be made by Hofmann but NOT Gabriel.