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Which of the following compounds exhibits geometrical isomerism?

1. CH2Cl2
2. CH2Cl-CH2Cl
3. CHBr=CHCl
4. CH2Cl-CH2Br

Correct answer: CHBr=CHCl

Solution

Geometrical isomerism in alkenes requires each doubly bonded carbon to carry two different groups. CHBr=CHCl satisfies this (one C has Br and H; the other has Cl and H), giving cis and trans isomers. The other compounds are single-bonded or have identical groups.

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