Exams › JEE Advanced › Chemistry
Correct answer: cyclohex-1,3-diene and 1-methylcyclopent-1-ene
Compound A: Cyclohex-1,3-diene on ozonolysis cleaves both double bonds (C1=C2 and C3=C4), producing succinaldehyde (OHC-CH2-CH2-CHO, from the C1-C2-C3-C4 fragment wait — actually C5-C6-C1 and C2-C3 fragments). The 4-C piece (C4-C5-C6-C1 with CHO at each end) is succinaldehyde, and the 2-C piece (C2-C3 with CHO at each end) is glyoxal. This matches. Compound B: 1-methylcyclopent-1-ene has C1(CH3)=C2 in a 5-membered ring. Ozonolysis opens the ring: C1 gives a ketone (CH3-CO-) and C2 gives an aldehyde (-CHO), yielding CH3-CO-CH2-CH2-CH2-CHO = 5-oxohexanal.