Exams › JEE Advanced › Chemistry
Correct answer: 500 m
Consider 1 litre of solution. Mass of solution = 1000 mL * 1.8 g/mL = 1800 g. Moles of H2SO4 = 18 mol. Mass of H2SO4 = 18 * 98 = 1764 g. Mass of water = 1800 - 1764 = 36 g = 0.036 kg. Molality = 18 mol / 0.036 kg = 500 mol/kg.