Exams › JEE Advanced › Chemistry
Lucas test (ZnCl2 + conc. HCl) gives immediate turbidity for which type of alcohol?
- Primary alcohol (1°-R-OH)
- Secondary alcohol (2°-R-OH)
- Tertiary alcohol (3°-R-OH)
- All types of alcohols
Correct answer: Tertiary alcohol (3°-R-OH)
Solution
Lucas test uses anhydrous ZnCl2 + concentrated HCl. The alcohol undergoes SN1 substitution to form an alkyl chloride (which is insoluble in the reagent, causing turbidity). The rate depends on carbocation stability. Tertiary alcohols form stable 3° carbocations instantly → immediate turbidity. Secondary alcohols react within ~5 min (mild turbidity). Primary alcohols do not react at room temperature (require heat). So immediate turbidity = tertiary alcohol.
Related JEE Advanced Chemistry questions
- Which compound listed below cannot be synthesized using the standard Williamson ether synthesis?
- In the reaction between C6H5Br and CH3CH2OH, C6H5Br remains unreactive. However, when C6H5OH reacts with MeCBrMe2, the tert-halide group in CBr undergoes elimination instead of substitution. Therefore, only certain combinations are suitable for ether synthesis.
- When CH3CH2CH2CH2OH is heated with Al2O3 at 350°C, what is the main product formed?
- The compound that does NOT liberate CO₂ on treatment with aqueous sodium bicarbonate solution, is -
- Which type of solution is required to perform the dye test for identifying β-naphthol?
- Among the following alcohols, how many will produce an immediate white turbidity (precipitate) when treated with Lucas reagent (anhydrous ZnCl2 / conc. HCl) at room temperature? The compounds are: (i) 1-butanol, (ii) 2-butanol, (iii) 2-methyl-2-propanol (tert-butanol), (iv) benzyl alcohol.
⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →