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How many litres of oxygen gas at STP (1 atm, 273 K) are required to completely burn 2.2 g of propane (C3H8)?

1. 11.2 L
2. 22.4 L
3. 5.6 L
4. 44.8 L

Correct answer: 5.6 L

Solution

Balanced equation: C3H8 + 5O2 -> 3CO2 + 4H2O. Moles of C3H8 = 2.2 / 44 = 0.05 mol. Moles of O2 required = 5 * 0.05 = 0.25 mol. Volume of O2 at STP = 0.25 * 22.4 = 5.6 L.

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