Exams › JEE Advanced › Chemistry
Correct answer: The oxidation number of Cr in the fusion product is +6.
Chromite ore = FeCr2O4, where Fe is in +2 state (option A says +2, which is actually correct for Fe). But the statement says iron in +2, which is correct for chromite. However, option B about Cr being +6 in fusion product is the most definitively correct statement. In Na2CrO4, Cr is +6. CrO4²- is tetrahedral with all equivalent Cr-O bonds (option C is also correct). Cr(VI) is d⁰, so no unpaired electrons, yet it shows colour due to charge transfer (option D - this statement claims no unpaired electron AND it is coloured, which is true but the reason is charge transfer not d-d transition). Among the options, B is the most clearly and unambiguously correct.