StreakPeaked· Practice

ExamsJEE AdvancedChemistry

Find the vapour density (VD) of a gaseous mixture of O3 and O2, where the molar ratio of O3 to O2 is 1: 2.

  1. 56/6
  2. 112/3
  3. 224/3
  4. 56/3

Correct answer: 56/3

Solution

Molar mass of O3 = 48 g/mol, O2 = 32 g/mol. Mole ratio O3:O2 = 1:2, so mole fractions are x(O3) = 1/3 and x(O2) = 2/3. Average molar mass = (1/3)*48 + (2/3)*32 = 48/3 + 64/3 = 112/3 g/mol. Vapour density = M_avg/2 = 112/6 = 56/3.

Related JEE Advanced Chemistry questions

⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →