Exams › JEE Advanced › Chemistry
Correct answer: OHC-CH2-CH2-CH2-CHO
Graham's law applied to molar rates gives M_A = 80 g/mol (C6H8, degrees of unsaturation = 3, confirmed by 3 mol H2 per mol A at STP). The six-membered monocyclic isomer of C6H8 is cyclohexadiene (uses 1 degree for ring, 2 for double bonds). 1,3-cyclohexadiene gives OHC-CHO and OHC-CH2-CH2-CHO on reductive ozonolysis. 1,4-cyclohexadiene gives two molecules of OHC-CH2-CHO. The 5-carbon dialdehyde OHC-CH2-CH2-CH2-CHO would require 5 carbons in a chain between two aldehyde groups, impossible from a 6-membered ring where cutting two double bonds always leaves fragments summing to 6 carbons with smaller chains.