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Among the elements F, C, N, O, Be, B, Na, Mg, how many have electronegativity greater than that of oxygen?

1. F
2. C
3. N
4. O

Correct answer: F

Solution

On the Pauling electronegativity scale: F=3.98, O=3.44, N=3.04, C=2.55, B=2.04, Be=1.57, Mg=1.31, Na=0.93. Among the given elements, only F (3.98) has electronegativity greater than O (3.44). So the answer is 1 element, which is F. The option listed as 'F' likely represents the answer of 1 element = Fluorine.

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