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ExamsJEE AdvancedChemistry

Match the following species with their spin-only magnetic moments: List-I (Species): (P) Cu+ (Q) Fe³+ (R) Mn⁴+ (S) Sc³+ List-II (Magnetic moment in units of mu_B): (1) 0 (2) sqrt(35) (3) sqrt(3) (4) sqrt(15) (5) sqrt(8) Select the correct matching.

  1. P -> 1; Q -> 5; R -> 4; S -> 3
  2. P -> 3; Q -> 5; R -> 3; S -> 1
  3. P -> 1; Q -> 2; R -> 4; S -> 1
  4. P -> 3; Q -> 2; R -> 5; S -> 3

Correct answer: P -> 1; Q -> 2; R -> 4; S -> 1

Solution

P) Cu+: [Ar]3d¹⁰, 0 unpaired electrons. mu = sqrt(0*2) = 0. -> (1). Q) Fe³+: [Ar]3d⁵, 5 unpaired electrons (high spin). mu = sqrt(5*7) = sqrt(35). -> (2). R) Mn⁴+: [Ar]3d³, 3 unpaired electrons. mu = sqrt(3*5) = sqrt(15). -> (4). S) Sc³+: [Ar]3d⁰, 0 unpaired electrons. mu = 0. -> (1). Correct matching: P->1, Q->2, R->4, S->1.

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