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ExamsJEE AdvancedChemistry

Given the following thermochemical data: cyclohexene + H2 (Ni catalyst) -> cyclohexane; delta_H = -28.6 kcal/mol Anthracene + excess H2 (Ni catalyst) -> fully hydrogenated anthracene; delta_H = -116.2 kcal/mol Calculate the resonance energy of anthracene.

  1. -84 kcal/mol
  2. -100 kcal/mol
  3. -110 kcal/mol
  4. -116 kcal/mol

Correct answer: -100 kcal/mol

Solution

Anthracene (C14H10) absorbs 5 mol H2 to become perhydroanthracene (C14H24). Theoretical heat of hydrogenation (assuming 5 isolated cyclohexene-like double bonds): 5 x (-28.6) = -143 kcal/mol. Actual: -116.2 kcal/mol. Resonance energy = actual - theoretical = -116.2 - (-143) = +26.8 kcal/mol (stabilization). But the question asks for resonance energy with sign convention used: RE = theoretical - actual = -143 - (-116.2) = -26.8 kcal/mol (magnitude ~27 kcal/mol). None of the options match exactly. However, using 7 double bonds (Kekule structure shows 7 pi bonds) and counting differently: if anthracene is treated as having 7 ring double bonds (like 3 benzene rings each with 3 double bonds = 9, minus 2 shared bonds = 7): theoretical = 7 x (-28.6) = -200.2 kcal/mol. RE = -116.2 - (-200.2) = +84 kcal/mol. So RE = -84 kcal/mol in the convention where RE is negative stabilization. Option A: -84 kcal/mol fits this calculation. Alternatively using (3 rings x 3 bonds - shared)/adjusted: RE = -84 kcal/mol.

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