Exams › JEE Advanced › Chemistry
When hydrated ferric chloride is dissolved in an aqueous solution that contains both oxalic acid and potassium hydroxide, the product obtained is
- A brown precipitate of Fe(OH)3 is obtained
- Green crystals of K3[Fe(C2O4)3] are obtained
- Yellow crystals of K[FeCl4] are obtained
- A yellow solution containing [Fe(H2O)6]Cl3 and K2C2O4 is obtained
Correct answer: Green crystals of K3[Fe(C2O4)3] are obtained
Solution
Hydrated FeCl3 in aqueous solution provides Fe3+ ions. Oxalic acid in the presence of KOH is converted to potassium oxalate (K2C2O4). The oxalate ion (C2O4²-) is a bidentate ligand that forms a highly stable complex with Fe3+. Three oxalate ions coordinate to one Fe3+ ion, and the K+ ions act as counter ions, giving the green crystalline compound K3[Fe(C2O4)3], potassium trioxalatoferrate(III).
Related JEE Advanced Chemistry questions
- The pair(s) of coordination complexes/ions exhibiting the same kind of isomerism is(are) -
- A 0.01 molal solution of a cobalt(III) chloride-ammonia complex, which dissociates completely, has a freezing point of -0.0558°C. Based on this data, how many chloride ions are present within the coordination sphere of the complex? [Kf for water = 1.86 K kg mol⁻¹]
- What are the molecular shapes of the ammonia complexes formed by Ni²⁺, Pt²⁺, and Zn²⁺, respectively?
- What are the spin-only magnetic moments (in Bohr Magneton) for the complexes [Cr(NH₃)₆]³⁺ and [CuF₆]³⁻, given that the atomic numbers of Cr and Cu are 24 and 29, respectively?
- When K3[Fe(CN)6] reacts with freshly prepared FeSO4, a dark blue solid known as Turnbull's blue is formed. On the other hand, when K4[Fe(CN)6] reacts with FeSO4 in the complete absence of air, a white solid X is produced, which later turns blue when exposed to air. Additionally, if FeSO4 is mixed with NaNO3 and concentrated H2SO4 is carefully added along the side of a test tube, a brown ring forms. What is the chemical identity of precipitate X?
- Which of the following compounds is responsible for the appearance of the brown ring?
⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →