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ExamsJEE AdvancedChemistry

What is the final product of the following reaction sequence? CaC2 --H2O--> [intermediate] --1% HgSO4 / dil. H2SO4--> [intermediate] --OH^(-) / heat-->

  1. CH3COCH=C(CH3)2
  2. CH3CH=CHCHO
  3. CH2=CHCHO
  4. CH3CH(OCH3)2

Correct answer: CH3COCH=C(CH3)2

Solution

CaC2 + H2O -> C2H2 (acetylene). C2H2 + H2O (HgSO4, H2SO4) -> CH3CHO (Markovnikov addition, Wacker-type). CH3CHO undergoes aldol condensation: 2 CH3CHO --OH^(-)--> CH3CH(OH)CH2CHO --(-H2O, heat)--> CH3CH=CHCHO (but-2-enal/crotonaldehyde). However, with further reaction, another aldol of crotonaldehyde or aldol of acetaldehyde could give a different product. The product CH3COCH=C(CH3)2 is more consistent with 3-molecule aldol of acetaldehyde sequence in some conditions. Let me reconsider: standard base-catalyzed aldol of acetaldehyde gives crotonaldehyde (CH3CH=CHCHO). The answer listed as (A) is mesityl oxide type. This question may be from a specific source where the intended answer is (B) crotonaldehyde.

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