Exams › JEE Advanced › Chemistry
Find the number of stereoisomers possible for the complex ion [Co(NH3)2(H2O)2ClBr]⁺.
- 5
- 6
- 8
- 10
Correct answer: 6
Solution
The complex [Co(NH3)2(H2O)2ClBr]⁺ has 6 coordination sites (octahedral). Ligands: 2xNH3, 2xH2O, 1xCl, 1xBr. This is an MA2B2CD type octahedral complex. For MA2B2CD, there are several geometric isomers. When the two A ligands (NH3) are trans to each other: fixed trans NH3. Then B2CD fills remaining 4 equatorial positions. B2(H2O) can be trans or cis: 2 sub-cases. When NH3 cis: more arrangements. Total geometric isomers = 6 for this type, and some may have optical isomers. Total stereoisomers = 6 (geometric only, no optical activity for most arrangements). Standard answer for [Co(NH3)2(H2O)2ClBr]⁺ is 6 stereoisomers.
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