Exams › JEE Advanced › Chemistry
Calculate the degree of dissociation of 0.1 N acetic acid (CH3COOH) given that its dissociation constant Ka = 1 * 10⁻⁵.
- 10⁻⁵
- 10⁻⁴
- 10⁻³
- 10⁻²
Correct answer: 10⁻²
Solution
For a weak acid: Ka = C * alpha², so alpha = sqrt(Ka / C) = sqrt(10⁻⁵ / 0.1) = sqrt(10⁻⁴) = 10⁻². Check: 0.01 << 1, so the approximation is valid.
Related JEE Advanced Chemistry questions
⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →