Exams › JEE Advanced › Chemistry
Correct answer: All are correct
CrO5 (chromium pentoxide or chromium peroxide): structure has one Cr=O group (oxygen ON = -2) and two peroxide groups (-O-O-) where each O has ON = -1. So there are 4 peroxide oxygen atoms (from two O-O groups) and 1 terminal oxygen. Total oxygen count: 5 = 4+1 (correct). ON check: Cr + 1*(-2) + 4*(-1) = 0 => Cr = +6. So: a is correct (Cr = +6); b is correct (4 oxygens in peroxide linkage); c is correct (only 1 oxygen has ON = -2). All statements correct.