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Chromite ore is fused with K2CO3 in the presence of air. The product gives a yellow solution Y. On acidification, Y gives an orange solution X. X is used as a powerful oxidizing agent. What are the oxidation states of the metal in the anion of X and Y respectively?

1. +6, +3
2. +6, +6
3. +3, +3
4. +3, +6

Correct answer: +6, +6

Solution

The process: 4FeCr2O4 + 8K2CO3 + 7O2 -> 8K2CrO4 (Y, yellow solution, chromate). 2K2CrO4 + H2SO4 -> K2Cr2O7 (X, orange, dichromate) + K2SO4 + H2O. In K2CrO4: oxidation state of Cr = +6. In K2Cr2O7: oxidation state of Cr = +6. So both X and Y have Cr in +6 state. Answer: +6, +6.

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