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Correct answer: I2 / NaOH (iodoform test)
Iodoform test (I2/NaOH) gives a yellow precipitate only with methyl ketones (CH3COR) or acetaldehyde. 2-pentanone has a CH3CO- group and gives positive iodoform test. 3-pentanone has no CH3CO- group and gives no iodoform. The other reagents (NaHSO3, NaCN, 2,4-DNP) react with both ketones similarly and cannot distinguish them.