Exams › JEE Advanced › Chemistry
The equilibrium constant for the reaction N2(g) + O2(g) ⇌ 2NO(g) is 4 * 10⁻⁴ at 200 K. In the presence of a catalyst, equilibrium is reached ten times faster. What is the equilibrium constant in the presence of the catalyst at 200 K?
- 40 * 10⁻⁴
- 4 * 10⁻⁴
- 4 * 10⁻³
- difficult to compute without more data
Correct answer: 4 * 10⁻⁴
Solution
Catalysts speed up the attainment of equilibrium by providing an alternative pathway with lower activation energy. They affect both the forward and reverse reaction rates equally, so the ratio of rate constants (which equals K) remains unchanged. Therefore, K = 4 * 10⁻⁴ at 200 K regardless of the presence of a catalyst.
Related JEE Advanced Chemistry questions
⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →