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Consider the disproportionation reaction: 3K2MnO4 + 2H2O + 4CO2 → 2X + Y + 4KHCO3. If the oxidation state of Mn in product X is n1 and in product Y is n2, find the value of (n1 + n2):

1. 9
2. 11
3. 13
4. 7

Correct answer: 11

Solution

K2MnO4 contains Mn in +6 state. On reaction with CO2 and water (acidic environment), Mn(+6) disproportionates: 2 moles form KMnO4 [Mn = +7] and 1 mole forms MnO2 [Mn = +4]. So X = KMnO4 (n1 = 7), Y = MnO2 (n2 = 4), n1 + n2 = 11. (The original options 1-4 appear to be a scanning artifact; correct answer is 11.)

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