Exams › JEE Advanced › Chemistry
Correct answer: Aniline (C6H5NH2) is a weaker base than benzylamine (C6H5CH2NH2)
All four options are evaluated: NH2⁻ is indeed a stronger base than OH⁻ (correct chemistry, option A is a true statement not an incorrect one); aniline is less basic than NH3 (true); CH3NH2 vs N(CH3)3 in water - due to solvation effects, trimethylamine is actually weaker than methylamine in some conditions, making C debatable; the most clearly and universally correct statement is D: aniline's N lone pair is delocalized into the ring making it much less basic than benzylamine where the CH2 spacer prevents delocalization.