Exams › JEE Advanced › Chemistry
Correct answer: CH3CH2CH2COONa treated with NaOH/CaO under heat (decarboxylation)
Options A (hydroboration of propene) and B (Wolff-Kishner on propanal) both yield propane; option D (decarboxylation of sodium butanoate) also gives propane. Option C gives 1-iodopropane, not propane. The canonical lab preparation is the decarboxylation route (D), but A and B are also valid. Given single-answer format, D is the expected answer as it is the classic named reaction for alkane preparation.