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Consider two reactions: Reaction 1: 3A + 2B -> A3B2 Reaction 2: A3B2 + 2C -> A3B2C2 Starting with 3 moles of A, 3 moles of B, and 1 mole of C, which of the following statements are correct?

1. 1 mole of A3B2C2 is formed
2. 1/2 mole of A3B2C2 is formed
3. 1/2 mole of B is left finally
4. 1/2 mole of A3B2 is left finally

Correct answer: 1/2 mole of A3B2C2 is formed

Solution

Reaction 1: 3A + 2B -> A3B2. With 3 mol A and 3 mol B, A is the limiting reagent (requires 3 mol A and 2 mol B). 1 mol A3B2 forms, 1 mol B remains. Reaction 2: 1 mol A3B2 + 2 mol C -> A3B2C2, but only 1 mol C available, so A3B2 is in excess. Moles of A3B2C2 formed = 1/2 mol. Remaining A3B2 = 1 - 1/2 = 1/2 mol.

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