Exams › JEE Advanced › Chemistry
Correct answer: Heating acetone with concentrated H2SO4
Acetone undergoes trimerisation in the presence of conc. H2SO4 on heating — three acetone molecules undergo aldol-type condensation and dehydration-aromatisation to give 1,3,5-trimethylbenzene (mesitylene). Trimerisation of propyne over Fe gives 1,3,5-trimethylbenzene too (option B is also correct). Zn-Hg/HCl reduces carbonyl to CH2 (Clemmensen), so 1,3,5-triformylbenzene (benzene-1,3,5-tricarbaldehyde) reduced by Clemmensen would give 1,3,5-tri(methyl)benzene only if the CHO is reduced to CH3 — but CHO -> CH3 requires two reductions; Clemmensen reduces CHO to CH2 (not CH3 if already CH2). Option D is not straightforward.