Exams › JEE Advanced › Chemistry
Correct answer: Ph-CO-CH2-CH3
Mercury(II)-catalyzed hydration of Ph-C≡C-CH3 follows Markovnikov's rule with electronic direction by the phenyl group, placing the hydroxyl on the carbon alpha to Ph. The resulting enol Ph-C(OH)=CHCH3 tautomerizes to the ketone Ph-CO-CH2CH3 (phenyl ethyl ketone).