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The solubility product of PbBr2 (molar mass = 368 g/mol) is 3.2 * 10⁻⁵. Assuming complete dissociation of the salt in solution, what is the solubility of PbBr2 in grams per litre?

1. 1.84
2. 3.68
3. 5.52
4. 7.36

Correct answer: 7.36

Solution

For PbBr2 dissociating completely, [Pb²+] = s and [Br⁻] = 2s. Setting 4s³ = 3.2*10⁻⁵ gives s = 0.02 mol/L. Multiplying by molar mass 368 g/mol yields 7.36 g/L.

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