For the reversible reaction: LaCl3(s) + H2O(g) + Heat LaClO(s) + 2HCl(g), equilibrium is established. If additional water vapour is introduced to disturb the equilibrium and the partial pressure of water vapour at the new equilibrium becomes twice that at the original equilibrium, by w

Question

For the reversible reaction: LaCl3(s) + H2O(g) + Heat <-> LaClO(s) + 2HCl(g), equilibrium is established. If additional water vapour is introduced to disturb the equilibrium and the partial pressure of water vapour at the new equilibrium becomes twice that at the original equilibrium, by what factor does the partial pressure of HCl change?

Accepted Answer

sqrt(2) times. For the equilibrium Kp = [p(HCl)]² / p(H2O). Since Kp is constant at fixed temperature, doubling p(H2O) means p(HCl)² must also double, so p(HCl) increases by a factor of sqrt(2).

Solution

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