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For the equilibrium SO3(g) ⇌ SO2(g) + (1/2) O2(g), a closed container initially holding pure SO3 reaches equilibrium at 400 K and a total pressure of 1 atm. If the degree of dissociation of SO3 at equilibrium is 2/3, what is the vapour density of the equilibrium mixture?

1. 30
2. 60
3. 40
4. 20

Correct answer: 30

Solution

Starting with 1 mol SO3, at alpha=2/3 the equilibrium mixture has 1/3 mol SO3, 2/3 mol SO2, and 1/3 mol O2 (total 4/3 mol). Mean molar mass = 80/(4/3) = 60 g/mol, so vapour density = 60/2 = 30.

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