Exams › JEE Advanced › Chemistry

For the equilibrium reaction 2BaO2(s) <=> 2BaO(s) + O2(g), delta-H is positive. At equilibrium, which of the following actions will increase the pressure of O2?

1. Adding more BaO2(s) to the system
2. Adding more BaO(s) to the system
3. Raising the temperature of the system
4. Adding more BaO2(s) and BaO(s) simultaneously

Correct answer: Raising the temperature of the system

Solution

Since both BaO2 and BaO are pure solids, Kp = P(O2). Kp is a function of temperature alone, and because delta-H > 0 (endothermic), raising T increases Kp, which directly increases the equilibrium pressure of O2.

Related JEE Advanced Chemistry questions

• In which of the following cases can the pH be determined using the equilibrium constant(s) provided?
• In the equilibrium reaction NH2COONH4(s) ⇌ 2NH3(g) + CO2(g), which change will cause the partial pressure of NH3 to rise?
• For the reaction XY2(g) ⇌ XY(g) + Y(g), if the value of α (degree of dissociation) is very small compared to 1, how is α related to the pressure (P)?
• At 460°C, 0.02 g of hydrogen reacts with 2.54 g of iodine until equilibrium is reached. Upon analysis, the equilibrium mixture contains 0.0021 moles of iodine. What is the equilibrium constant (Kc) for this reaction?
• Determine the pH of a 1.0 M solution of an unidentified hydroxide compound, assuming the metal ion has a +1 charge.
• What explains the acidic nature of an aqueous solution of aluminum chloride?

⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →