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ExamsJEE AdvancedChemistry

Ni²+ forms complexes with coordination number 4. Given the reactions: NiCl2 + excess KCN -> Complex A NiCl2 + excess KCl -> Complex B What are the hybridisations of the central metal in A and B respectively?

  1. dsp2, sp3
  2. sp3, sp3
  3. dsp2, dsp2
  4. sp3d2, d2sp3

Correct answer: dsp2, sp3

Solution

CN⁻ is a strong-field ligand that forces pairing of the d⁸ electrons in Ni²+, vacating one d orbital, leading to dsp2 square planar geometry for complex A. Cl⁻ is a weak-field ligand that does not cause pairing, so complex B adopts sp3 tetrahedral geometry.

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