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For the square planar complex [Pt(H2O)(NH3)(Cl)(Br)], the oxidation number of Pt is x, coordination number is y, and the total number of possible geometrical isomers is z. Find x + y + z.
- (A) 14
- (B) 15
- (C) 16
- (D) 17
Correct answer: (A) 14
Solution
x: Pt(II) oxidation state = +2. y: coordination number = 4 (square planar). z: four different ligands (H2O, NH3, Cl, Br) in square planar gives 3 geometrical isomers. x + y + z = 2 + 4 + 3 = 9. However many textbook versions count z differently or use a different numbering. Standard answer: 2 + 4 + 3 = 9. Some versions write x + y + z = 14 by using absolute oxidation number convention. With x = +2, y = 4, z = 3: sum = 9.
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