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The initial rate of hydrolysis of methyl acetate (1 M) by a weak acid (HA, 1 M) is 1/100th of that of a strong acid (H x, 1 M), at 25°C. The Ka of HA is -

1. 1 × 10⁻⁴
2. 1 × 10⁻⁵
3. 1 × 10⁻⁶
4. 1 × 10⁻³

Correct answer: 1 × 10⁻⁴

Solution

The rate of hydrolysis depends on the concentration of H⁺ ions. Since the weak acid's rate is 1/100th of the strong acid's, its Ka must be 1 × 10⁻⁴ to produce the corresponding H⁺ concentration.

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