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Upon treatment with ammoniacal H₂S, the metal ion that precipitates as a sulfide is -

1. Fe(III)
2. Al(III)
3. Mg(II)
4. Zn(II)

Correct answer: Zn(II)

Solution

Zn(II) forms a sulfide precipitate with ammoniacal H₂S due to its solubility product being exceeded, unlike the other metal ions listed.

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