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ExamsJEE AdvancedChemistry

For the following reaction the equilibrium constant Kₑ at 298 K is 1.6 × 10¹⁷: Fe²⁺(aq) + S²⁻(aq) ⇌ FeS(s) When equal volumes of 0.06 M Fe²⁺(aq) and 0.2 M S²⁻(aq) solutions are mixed, the equilibrium concentration of Fe²⁺(aq) is found to be Y × 10⁻¹⁷ M. The value of Y is ____.

  1. 8
  2. 8.3
  3. 8.5
  4. 9

Correct answer: 8.3

Solution

The equilibrium constant is extremely large, indicating that almost all Fe²⁺ reacts to form FeS. Using the equilibrium expression and given concentrations, the remaining Fe²⁺ concentration is calculated to be 8.3 × 10⁻¹⁷ M.

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