Exams › JEE Advanced › Chemistry
On dissolving 0.5 g of a non-volatile non-ionic solute to 39 g of benzene, its vapor pressure decreases from 650 mm Hg to 640 mm Hg. The depression of freezing point of benzene (in K) upon addition of the solute is ____. (Given data: Molar mass and the molal freezing point depression constant of benzene are 78 g mol⁻¹ and 5.12 K kg mol⁻¹, respectively)
- 1.0256
- 1.026
- 1.03
- 1.04
Correct answer: 1.04
Solution
The depression in freezing point is calculated using the formula ΔTf = Kf × m, where m is the molality. Using the given data and solving for molality, the depression in freezing point is approximately 1.04 K.
Related JEE Advanced Chemistry questions
⚔️ Practice JEE Advanced Chemistry free + battle 1v1 →