Exams › IBPS PO › Reasoning
Statement: P & R % T Q @ M Conclusions: I. Some R being not Q is a possibility. II. All M can be T. III. Some T being not P is a possibility. IV. All P can never be R.
- Both III and IV
- Only I
- Both II and III
- Only IV
- Only III
Correct answer: Both III and IV
Solution
The symbol chain gives relations among P, R, T, Q, and M. Conclusion III is possible because T can include elements outside P without contradicting the given relations. Conclusion IV is also valid because the given relations do not allow all P to be R. Conclusions I and II do not follow from the chain.
Related IBPS PO Reasoning questions
- Directions (43–45): In these questions, symbols ©, #, %, and @ are used with different meanings as follows: \(M © N\) means \(M\) is smaller than \(N\); \(M # N\) means \(M\) is either smaller than or equal to \(N\); \(M % N\) means \(M\) is greater than \(N\); \(M \ge N\) means \(M\) is either greater than or equal to \(N\); \(M @ N\) means \(M\) is neither smaller than nor greater than \(N\). Assuming the given statements to be true, find out which of the conclusions I, II and III given below are definitely true. Statements: \(B \; D \; % \; G @ Q;\; L # M © N # Q;\; M P % U\) Conclusions: I. \(D % U\) II. \(N % G\) III. \(M @ B\)
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