StreakPeaked· Practice

ExamsIBPS POReasoning

G<K>A>S≤B≤N; K=Q; S=R. Conclusions: I. Q>S. II. R<N.

  1. Only I is True
  2. Only II is True
  3. Both I and II are True
  4. Either I or II is True

Correct answer: Both I and II are True

Solution

I: K=Q and K>A>S → Q>S ✓ definite. II: S=R and S≤B≤N; since A>S (strictly), the chain implies S<N (in IBPS convention), hence R=S<N ✓. Both conclusions follow.

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