StreakPeaked· Practice

ExamsIBPS POReasoning

P<Q≥G; G≥I≥E; C<P; C>U. I: U>I. II: P<E.

  1. Both I and II are True
  2. Only II is True
  3. Neither I nor II is true
  4. Only I is True

Correct answer: Neither I nor II is true

Solution

I: U<C<P and G≥I≥E, but P<Q≥G: could have I>P or I<P, so U vs I is not fixed. II: P<Q and Q≥G≥I≥E, but since P<Q and I≤Q, P could be > or < E. Neither conclusion is definite.

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