StreakPeaked· Practice

ExamsIBPS POReasoning

In 'BONAFIDE', how many pairs of letters have the same number of letters between them (in both word and alphabet)?

  1. Four
  2. More than Four
  3. One
  4. Three

Correct answer: More than Four

Solution

Positions in word: B=1,O=2,N=3,A=4,F=5,I=6,D=7,E=8. Alphabet values: B=2,O=15,N=14,A=1,F=6,I=9,D=4,E=5. Valid pairs where |pos_diff|=|alpha_diff|: BF(4=4)✓, ON(1=1)✓, AD(3=3)✓, AE(4=4)✓, FD(2=2)✓, DE(1=1)✓ = 6 pairs.

Related IBPS PO Reasoning questions

⚔️ Practice IBPS PO Reasoning free + battle 1v1 →