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ExamsIBPS POReasoning

In this input-output question, numbers are arranged in ascending order from both ends, such that the lowest number is placed first from the left end and the second-lowest number is placed from the right end. Also, each number being arranged is increased by 1. Input: 58 40 99 28 63 84 16 34 71 87 Step I: 17 58 40 99 63 84 34 71 87 29 Step II: 35 17 58 99 63 84 71 87 29 41 Step III: 59 35 17 99 84 71 87 29 41 64 Step IV: 72 59 35 17 99 87 29 41 64 85 Step V: 88 72 59 35 17 29 41 64 85 100 What is the last number in the final step?

  1. 99
  2. 100
  3. 85
  4. 100

Correct answer: 100

Solution

The pattern places the next smallest transformed number alternately from the left and right ends. In the final step, the last position contains the transformed largest number, which is 100.

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