StreakPeaked· Practice

ExamsIBPS POReasoning

Eight persons P, Q, R, S, T, U, V and W were born in different years 1982, 1986, 1990, 1993, 1996, 1999, 2000 and 2009, but not necessarily in the same order. It is assumed that all of them were born on the same date in different years. All age calculations are done taking the base year as 2021. - Two persons were born between R and Q. - The age of R is a perfect square. - One person was born between Q and W. - Three persons were born between W and V. - P is younger than V and older than R. - The age of P is a multiple of 7. - The sum of V's age and S's age is 56. - The difference between the ages of S and T is 18. Who was born in 1990?

  1. Q
  2. V
  3. P
  4. T

Correct answer: Q

Solution

This is an age-and-year arrangement puzzle. Using the spacing conditions and the age constraints, the unique arrangement places Q in the year 1990. Therefore, Q was born in 1990.

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