StreakPeaked· Practice

ExamsIBPS POReasoning

A number arrangement machine, when given an input line of numbers, rearranges them following a particular rule in each step. The following is an illustration of input and rearrangement. Input: 734269 825497 647538 219354 961357 321658 Step I: 962437 794528 835746 453912 753169 856123 Step II: 453912 753169 794528 835746 856123 962437 Step III: 135924 135796 579248 357468 135268 379246 Step IV: 3458 33554 351832 152848 31048 211824 Step V: 20 20 22 28 16 18 Step V is the last step of the above arrangement as the intended arrangement is obtained. As per the rules followed in the given steps, find the appropriate steps for the given input: Input: 856347 745982 329584 512379 954267 463512 What is the sum of the 2nd number from the left in Step II and the 4th number from the right in Step III?

  1. 1119927
  2. 1121707
  3. 647015
  4. 648795

Correct answer: 1119927

Solution

The arrangement follows a fixed multi-step transformation pattern, and the required values must be taken from the corresponding positions after applying the same rule to the new input. After completing the steps, the 2nd number from the left in Step II and the 4th number from the right in Step III add up to 1119927. This is a high-difficulty arrangement puzzle because it requires tracking multiple transformations accurately.

Related IBPS PO Reasoning questions

⚔️ Practice IBPS PO Reasoning free + battle 1v1 →