Exams › IBPS PO › Reasoning

Logic: In the given input-output, numbers are arranged from both ends simultaneously. In the first step, the lowest number is arranged from the left end and the highest from the right end. In the second step, the second lowest from the left, the second highest from the right, and so on. Numbers from the left end are replaced by the sum of digits; from the right end by the difference of digits. Input: 75 12 10 94 84 32 63 42 54 22 Step I: 01 75 12 84 32 63 42 54 22 05 Step II: 03 01 75 32 63 42 54 22 05 04 Step III: 04 03 01 32 63 42 54 05 04 02 Step IV: 05 04 03 01 42 54 05 04 02 03 Step V: 06 05 04 03 01 05 04 02 03 01 What is the number at the 6th position from the left in Step IV?

1. 1
2. 5
3. 54
4. 3

Correct answer: 3

Solution

In Step IV, the sequence is 05 04 03 01 42 54 05 04 02 03. Counting from the left, the 6th position is 54. However, the keyed answer in the source is 3, indicating the question or answer key is inconsistent.

Related IBPS PO Reasoning questions

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