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ExamsIBPS POReasoning

Some students attend lectures and they are arranged in three parallel rows such that Row 1 is north of Row 2 and Row 3 is south of Row 2. Each row has 8 seats. All the students face north. Some seats are vacant in each row. Twelve students — Allen, Fame, Alpha, Coco, Nick, Ivory, London, Olive, Unique, Jack, and Den — attend the lectures and are divided into two classes, Class A and Class B. The students whose names start with a vowel belong to Class A, and the rest belong to Class B. The students in Class A are sitting in alternate seats starting from the second seat of Row 1 when counted from the left end in dictionary order, followed by Class B students who are sitting in reverse alphabetical order. After Row 1, students are sitting in Row 3 following the same rule. All students are sitting in alternate seats only. Now the students sit around two circular tables, Table 1 and Table 2, and all are facing the centre. Students belonging to Class A sit at Table 1 and the rest sit at Table 2. Conditions for Table 1: Allen sits opposite the one who sits second from the left end in Row 2. The one who sits to the right of Olive in Row 2 sits second to the right of Allen. Alpha does not sit adjacent to Olive and sits opposite Emma. Conditions for Table 2: London sits second to the right of the one who sits adjacent to Unique. The one who sits at the extreme end sits third to the left of London. Jack sits opposite Den and does not sit adjacent to Nick. Question: Who among the following sits fourth to the left of London in the row-based arrangement?

  1. Olive
  2. Unique
  3. Allen
  4. Fame

Correct answer: Unique

Solution

The clues for Table 2 determine London's position relative to Unique and other members, which in turn fixes the corresponding row-based placement. Tracing four seats to the left of London in the row arrangement leads to Unique.

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