In a hexagon arrangement, at each corner, a triangle is placed, denoted by either two letters or two numbers. Below are the conditions: I. If a number is a perfect square, then only that number is increased by 1. II. If there is at least one vowel, change it to the preceding alphabet. III.

Question

In a hexagon arrangement, at each corner, a triangle is placed, denoted by either two letters or two numbers. Below are the conditions: I. If a number is a perfect square, then only that number is increased by 1. II. If there is at least one vowel, change it to the preceding alphabet. III. If both digits are odd, then reduce those digits by 2. IV. If any one of the consonants is smaller than N in alphabetical order, then change it to the next alphabet. Note: If no condition is applied, there will be no change. More than one condition may be applicable. Example: Triangle 1: (1,4) → (2,5) Triangle 2: (o,k) → (n,l) Triangle 3: (6,7) → (6,7) Triangle 4: (i,l) → (h,m) Triangle 5: (s,v) → (S,V) Triangle 6: (5,5) → (3,3) Input: Triangle 1: (c,d) Triangle 2: (u,b) Triangle 3: (7,7) Triangle 4: (h,f) Triangle 5: (w,q) Triangle 6: (8,3) What is the sum of the second number of the output of Triangle 3 and the first number of the output of Triangle 6?

Accepted Answer

13. Triangle 3 is (7,7); both digits are odd, so each is reduced by 2 to get (5,5), making the second number 5. Triangle 6 is (8,3); 8 is a perfect square? No, but 3 is a perfect square, so only 3 increases to 4, giving (8,4). The required sum is 5 + 8 = 13.

Solution

Related IBPS PO Reasoning questions